z^2+4z+3=(z+5)(z+6)

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Solution for z^2+4z+3=(z+5)(z+6) equation: 



z^2+4z+3=(z+5)(z+6)

We move all terms to the left:

z^2+4z+3-((z+5)(z+6))=0

We multiply parentheses ..

z^2-((+z^2+6z+5z+30))+4z+3=0



We calculate terms in parentheses: -((+z^2+6z+5z+30)), so:

(+z^2+6z+5z+30)

We get rid of parentheses

z^2+6z+5z+30

We add all the numbers together, and all the variables

z^2+11z+30

Back to the equation:

-(z^2+11z+30)



We add all the numbers together, and all the variables

z^2+4z-(z^2+11z+30)+3=0

We get rid of parentheses

z^2-z^2+4z-11z-30+3=0

We add all the numbers together, and all the variables

-7z-27=0

We move all terms containing z to the left, all other terms to the right

-7z=27

z=27/-7

z=-3+6/7

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